AdHoc API -- Routing protocol?

AdHoc API -- Routing protocol?

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Good morning,

I would know if the AdHoc library provide some sort of routing. I will explain better with an example, see the image below:

We have 3 peer "A", "B" and "C"

"A" wifi coverage can reach only peer "B"
"B" wifi can reach peer "A" and peer "C"
"C" wifi can reach only peer "B"

If "C" call the "GetListOfLocalUsers()" method it obtain a list with peer "A" AND peer "B" or only the peer "B"?

If "C" got a list wich contain "A" and "B" it can send a message to peer "A" without worrying about routing, isn't it? (the routing is transparent to "C")

I hope someone can help me to understand this trouble.

Thanks

sorry for my poor english

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Bild des Benutzers Lester Memmott (Intel)

Serfio, It might help if you can tell us what development library you are using that contains this GetListOfLocalUsers() method.

Bild des Benutzers serfio
Quoting - Lester Memmott (Intel)
Serfio, It might help if you can tell us what development library you are using that contains this GetListOfLocalUsers() method.

I'm using the "Intel laptop gaming TDK v2.1" wich contains "IntelLaptopGaming.dll" and "AdhocAPI.dll".

The "GetListOfLocalUsers()" is contained into "AdhocAPI.dll"

thanks

Bild des Benutzers lqnguyen
Quoting - serfio Good morning,

I would know if the AdHoc library provide some sort of routing. I will explain better with an example, see the image below:

We have 3 peer "A", "B" and "C"

"A" wifi coverage can reach only peer "B"
"B" wifi can reach peer "A" and peer "C"
"C" wifi can reach only peer "B"

If "C" call the "GetListOfLocalUsers()" method it obtain a list with peer "A" AND peer "B" or only the peer "B"?

If "C" got a list wich contain "A" and "B" it can send a message to peer "A" without worrying about routing, isn't it? (the routing is transparent to "C")

I hope someone can help me to understand this trouble.

Thanks

sorry for my poor english

Hi,

If C calls GetListOfLocalUsers, C should see only B. Therefore, your second question cannot happen.

Hope this help,
Loc

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