is there a simple way to convert a 16s image to 16u , without going creating temporary 32s
image and adding 32768 to each pixel ?
16s to 16u conversion
Wed, 01/12/2011 - 10:29
16s to 16u conversion
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Wed, 01/12/2011 - 11:22
Hello,
IPP v7.0 contain appropriate convertion functions in image processing domain
IPPAPI ( IppStatus, ippiConvert_16s16u_C1Rs,
(const Ipp16s* pSrc, int srcStep, Ipp16u* pDst, int dstStep,
IppiSize roi))
Although, it is implemented asdst[n] = (src[n]>0)?(Ipp16u)src[n]:0; that might be not what you are looking for
Regards,
Vladimir
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Wed, 01/12/2011 - 11:26
yeah witht aht conversion i would lose all the pixels with negative value , definetly not what i want :)
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Wed, 01/12/2011 - 23:55
Hi!
Forrange shift (16s => 16u) you can use function ippiXorC_16u_C1IR:
ippiXorC_16u_C1IR(0x8000, (Ipp16u *)pSrcDst, srcDstStep, roiSize).
Data are converted:
-32768 -> 0,
-32767 -> 1,
...
-1 -> 32767,
0 -> 32768,
1 -> 32769,
...
32767 -> 65536.
For processing of images with 3, 4 channels use similar functions with suffixesC3, C4.
I hope you are finding it.