Hi Trying to have large arbb function, i face a problem with executing function captured by arbb. Here is the small exemple i took : // a small class
class PayOffSoSimple { public : PayOffSoSimple() {} PayOffSoSimple( const PayOffSoSimple & pay) {} arbb::f64 operator()() const { return 1.; } }; // a first caller with payoff function instanciated inside the caller void caller_( const arbb::usize & N) { PayOffSoSimple pay; arbb::dense Sol(N); _for (arbb::usize i= 0 , i < N , ++i) { Sol[i] = pay(); } _end_for; } // a second one with the pay off as argument void caller( const PayOffSoSimple & pay, const arbb::usize & N) { arbb::dense Sol(N); _for (arbb::usize i= 0 , i < N , ++i) { Sol[i] = pay(); } _end_for; } int main(int argc, char *argv[]) { arbb::usize N_ = 10 ; PayOffSoSimple paySoSimple; // OK arbb::dense sol(N_) ; _for (arbb::usize i= 0 , i < N_ , ++i) { sol[i] = paySoSimple(); } _end_for; // OK arbb::call(caller_)(N_); // exception arbb::call(caller)(paySoSimple,N_); return 0 ; } here is the exception : terminate called after throwing an instance of 'arbb_2::exception' what(): zero types captured Aborted Why is the second caller impossible to use ? Thank you Sincerely yours.