floating point operation result out of range in static initialization

Reference number : DPD200155372

Product :  Intel® C++ Compiler Professional Edition for Linux 11.1

Environment : Linux, C


This KB can be treated as "NOT a DEFECT" in Intel Compilers, but rather a "Technical Note/Tips", reason provided further on.

#include <stdio.h>

  static long double nan = { 0.0L / 0.0L };
  static long double plus_in = 1.0L / 0.0L;
  static long double minus_in = -1.0L / 0.0L;

int main()
return 1;

The above code in .c (using icc) gives error: error: floating-point operation result is out of range
The gcc compiler compiles successfully.


1) However, if the static variables are declared then defined (as like compile-time constants) , then its accepted as C code.
2) Rename .C to .cpp file, and again the icc compiles it successfully, as C++ allows runtime initialization of static objects.
3) While still a .C file, use icpc instead of icpc, and its treated with a C++ driver, and compiles okay.
4) Convert static to local variables (or auto keyword) in case the static initialization is not enforced on variables by the application.
5) There are a few built-ins which can accomplish the same job, without a quiver, and its as good as a fix.
you can use these:--

long double nan = ((__builtin_nanl("")));
long double plus_in = ((__builtin_huge_vall()));
long double minus_in = ((-__builtin_huge_vall()));

Root Cause : 
The situation described (i.e. that the compiler works differently between C and C++) is not a bug. It reflects the fact that run-time initialization of static objects is allowed in C++, but not in C. However, what is a bug is the fact that Intel compilers rejects it while GCC accepts it without a quiver, even in C.

Resolution :  This issue MAY be fixed in the later release of Intel® C++ compilers, since its only the different way the gcc treats it, and is not a defect in the true sense. This KB can also be treated as "NOT a DEFECT", but rather a "Technical Note/Tips"

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