# How to find max of two images

## How to find max of two images

We would like to be able to generate an image buffer whose pixel values are the maximum of two other buffers (or perhaps the current and one other buffer).

In other words, for every pixel, i, m[ i ] = max( a[ i ], b[ i ] ) or m[ i ] = max ( m[ i ], a[ i ] ).

Any suggestions for how to do this? I didn't see a function to do exactly this. Perhaps we need to make several calls, but wanted to see if others had some suggestions.

Thank you

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Hi Paul,

Please see my "feature request" at

http://softwareforums.intel.com/ids/board/message?board.id=IPP&message.id=1365&highlight=andrew#M1365

Areyou ready to submit another "feature request" on premier site to see it done?

Thanks,

Andrew

Hi, it seems in case of Ipp8u data type we can do it in two simple operations:

Input: A, B
Output: C

C = A B;
C = C + B;

Due to saturation used in ippi functions there will be correct result
C = MAX(A,B);

Or if go more deeply simple for loop with only several intrinsics inside:

movdqa regA, A
movqda regB, B
pmaxub regA, regB
movdqa C, regA

Regards,

Can you explain (or point to somewhere this is explained) how saturation works? I'm trying to understand how C = A-B, C= C+B will work. For example, for pixel i, if A[ i ] = 5 and B[ i ] = 10, then C[ i ] will equal what? -5?, 0? Does saturation work by truncating negative values to 0 and values larger than 255 (assuming 8-bits) to 255?

A = 5
B = 10
C = A B = 5 10 = -5 = > (saturate to 8u means range 0 <= X <= 255 => 0;
C = C + B = 10;
It is true for all functions with _Sfs suffix and unsigned data type.

Regards,

Will this work the same with

ippiSub_32sc_C1RSfs

and