What is the latency and throughput of the vbroadcastsd instruction?

What is the latency and throughput of the vbroadcastsd instruction?

Hi,

I was wondering what is the latency and throughput of the vbroadcastsd instruction? (This is
for Sandy Bridge)

I did not find that information in the Optimization Reference Manual.

Thanks!

-Jeremy

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Para obter mais informações sobre otimizações de compiladores, consulte Aviso sobre otimizações.

According to Agner Fog's instruction tables it has a 1 / cycle throughput, like every other shuffle type instruction. The latency is mainly determined by the memory access. A load from L1 cache takes 4 cycles, and the broadcast itself should take 1 cycle. There might also be a penalty of 1 or 2 cycles for crossing domains (I don't remember if that applies here). In any case this is a fast instruction for what it's designed to do.

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