As given in Demo Scenario
MyApp.exe 1BFC91544B9CBF9E5B93FFCAB7273070 38040301052B0163A103400502060501 05ED2F440000B17B0000000100000036
expected result is 4774 cycles
My understanding of problem
DWord addition will be = 4774 / 37 = 129 times
ByteAddition = 4774 - 129 = 4645 times
Since 0x70 is least significant byte in DWord so after 4774 cycles it should be = (0x70 + 4645 * 0x01 + 129 * 0x36)%256 = 203
Please let me know the what I misunderstood from problem statement?